### Bit & Baud Rate - Rensselaer Polytechnic Institute

2013-11-23 · Thus, the gross bit rate is: R = baud rate x log 2S = baud rate x 3.32 log 10S If the baud rate is 4800 and there are two bits per symbol, the number of symbols is 2 2 = 4. The bit rate is: R = 4800 x 3.32 log(4) = 4800 x 2 = 9600 bits/s If there’s only one bit per symbol, as is the case with binary NRZ, the bit and baud rates remain the same.

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