Last updated at Aug. 11, 2021 by Teachoo
Transcript
Ex 8.3, 2 Show that : tan 48 tan 23 tan 42 tan 67 = 1 Taking L.H.S tan 48 tan 42 tan 23 tan 67 = tan 48 tan(90 48 ) tan 23 tan(90 23 ) = tan 48 cot 48 tan 23 cot 23 = (tan 48 1/tan 48 ) (tan 23 1/tan 23 ) = 1 1 = 1 = R.H.S L.H.S = R.H.S Hence proved
Trignometric ratios of complementry angles
Example 9 Deleted for CBSE Board 2022 Exams
Ex 8.3, 1 (i) Deleted for CBSE Board 2022 Exams
Ex 8.3, 2 (i) Important Deleted for CBSE Board 2022 Exams You are here
Ex 8.3, 7 Deleted for CBSE Board 2022 Exams
Example 11 Important Deleted for CBSE Board 2022 Exams
Ex 8.3, 4 Deleted for CBSE Board 2022 Exams
Example 10 Important Deleted for CBSE Board 2022 Exams
Ex 8.3, 3 Deleted for CBSE Board 2022 Exams
Ex 8.3, 5 Important Deleted for CBSE Board 2022 Exams
Ex 8.3, 6 Important Deleted for CBSE Board 2022 Exams
Trignometric ratios of complementry angles
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